Consider the following hypothesis test: $H_0: μ = 15$ $H_a: μ ≠ 15$. A sample of 50 provided a sample mean of 14.15. The population standard deviation is 3. Compute the value of the test statistic. |
-1.42 -2 -2.57 -3 |
-2 |
The correct answer is Option (2) → -2 Given $μ_0 = 15, n = 50, \bar x = 14.15, σ = 3$ $Z=\frac{\bar x-μ_0}{\frac{σ}{\sqrt{n}}}=\frac{14.15-15}{\frac{3}{\sqrt{50}}}=\frac{-0.85×\sqrt{50}}{3}$ $=-2.003$ $∴Z=-2$ |