Practicing Success
Practicing Success
CUET Preparation Today
If secθ + tanθ = 2, then the value of secθ.tanθ is? |
\(\frac{3}{16}\) 1 \(\frac{15}{16}\) \(\frac{2}{3}\) |
\(\frac{15}{16}\) |
secθ + tanθ = 2 ⇒ secθ - tanθ = \(\frac{1}{2}\) 4secθ.tanθ = (secθ + tanθ)2 - (secθ - tanθ)2 ⇒ 4secθ.tanθ = (2)2 - (\(\frac{1}{2}\))2 ⇒ 4secθ.tanθ = 4 - \(\frac{1}{4}\) ⇒ secθ.tanθ = \(\frac{15}{16}\) |
