If secθ + tanθ = 2, then the value of secθ.tanθ is?
Answer & explanation
Correct answer: option 3
secθ + tanθ = 2
⇒ secθ - tanθ = \(\frac{1}{2}\)
4secθ.tanθ = (secθ + tanθ)2 - (secθ - tanθ)2
⇒ 4secθ.tanθ = (2)2 - (\(\frac{1}{2}\))2
⇒ 4secθ.tanθ = 4 - \(\frac{1}{4}\)
⇒ secθ.tanθ = \(\frac{15}{16}\)