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What is the de Broglie wavelength of an electron with kinetic energy of 81 eV? |
0.136 nm 0.712 nm 0.512 nm 4 nm |
0.136 nm |
The de Broglie wavelength is given by \(\lambda \) =\(\frac{h}{\sqrt {2mK}}\) Kinetic energy, K = 81 eV = 81×1.6×10-19 J \(\lambda \) = \(\frac{6.626 × 10^{-34}}{\sqrt{2 × 9.1 × 10^{-31} × 81 × 1.6 × 10^{-19}}}\) = 0.136 nm |
