Amit, Sumit and Puneet were doing shooting. Amit hits the target 4 times in 5 shots, Sumit hits the target 3 times in 4 shots and Puneet hits the target 2 times in 3 shots.
Then the probability that Amit, Sumit and Puneet all may hit the target is :
Answer & explanation
Correct answer: option 2
A → Amit hits the target
S → Sumit hits the target
P → Puneet hits the target
from data,
so $P(A) = \frac{4}{5}, ~~P(S) = \frac{3}{4},~~P(P) = \frac{2}{3}$
Probability that all three hit target
= P(A) P(S) P(P)
= $\frac{4}{5} × \frac{3}{4} × \frac{2}{3}$
= $\frac{2}{5}$