If sinθ = \(\frac{8}{15}\), then what is the value of tanθ + cotθ ? |
1 \(\frac{136}{353}\) \(\frac{353}{136}\) 0 |
\(\frac{353}{136}\) |
sinθ = \(\frac{8}{15}\) ⇒ sinθ = \(\frac{8(P)}{15(H)}\) using Pythagoras theorem , Base = 17 tanθ + cotθ = \(\frac{P}{B}\) + \(\frac{B}{P}\) = \(\frac{8}{17}\) + \(\frac{17}{8}\) = \(\frac{353}{136}\) |