A starts from a point at a speed of 34 m/s. After 5 seconds, B starts chasing A from the same point at a speed of 44 m/s. What will be the distance travelled by B before A is caught by B?

748 metres

Distance covered by A in 5 sec = 34 × 5 =  170

Relative = ( 44 - 34 )m/sec = 10 m/sec

Time taken by A to caught B = \(\frac{170}{10}\) = 17 sec

Total distance traveled by B = 170 + 34 × 17  = 170 + 568

= 748 m