Avinash has 20% less coins of different countries than Gaurav has. Gaurav has 40% more such coins than Chetan has. By what percent the number of coins which Chetan has is less than the number of coins which Avinash has? (correct to one decimal place)
Answer & explanation
Correct answer: option 1
40% = \(\frac{2}{5}\) , 20% = \(\frac{1}{5}\)
Let Number of coins chetan has = 100
Number of coins of Gaurav = 100 +100 × \(\frac{2}{5}\) = 140
Number of coins of Avisnash = 140 - 140 × \(\frac{1}{5}\) = 112
Difference in coins of Chetan & Anivash = 112 - 100 = 12
Required percentage = \(\frac{12}{112}\) × 100% = 10.71%
= 10.7%