Avinash has 20% less coins of different countries than Gaurav has. Gaurav has 40% more such coins than Chetan has. By what percent the number of coins which Chetan has is less than the number of coins which Avinash has? (correct to one decimal place)

10.7

40% = \(\frac{2}{5}\) , 20% = \(\frac{1}{5}\)

Let Number of coins chetan has = 100

Number of coins of Gaurav = 100 +100 × \(\frac{2}{5}\) = 140

Number of coins of Avisnash = 140 - 140 × \(\frac{1}{5}\) = 112

Difference in coins of  Chetan &  Anivash = 112 - 100 = 12

Required percentage =  \(\frac{12}{112}\) × 100% = 10.71%

=  10.7%