Find the average of cubes of natural numbers till 7.

Sum of cube of n natural numbers = n² × \(\frac{(n + 1)(n + 1)}{4}\)

Here n = 7

Sum of cube of 7 natural numbers =  7² × \(\frac{(7 + 1)(7 + 1)}{4}\) = 784

Now, the average of cube of first 7 natural numbers= \(\frac{784}{7}\) = 112