Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

One microfarad capacitor of a TV is subjected to 4000V potential difference. What is the energy stored in the capacitor?

Options:

8 J

16 J

10 J

4 J

Correct Answer:

8 J

Explanation:

Energy stored in a capacitor : U = \(\frac{1}{2}\) C V2

C = 1 x 10-6 F ; V = 4000 V

U = 8 J