AB and CD are two chords of a circle which intersect at E inside the circle. If ∠BEC = 125° and ∠EBD = 28°, then what is the measure of ∠BAC ?
Answer & explanation
Correct answer: option 3
As, CD is a straight line.
So, ∠BEC + ∠BED = 180º
125º + ∠BED = 180º
∠BED= 55º
In triangle BED,
∠B + ∠E + ∠D = 180º
28º + 55º + ∠D = 180º
∠D = 97º
Property we going to use here is :- Angles made by same segment on circumference are equal.
⇒ ∠D = ∠A
So, ∠A = 97º
Hence , ∠BAC = 97º