In the given figure, if PQ = 13 cm and PR = 12 cm, then the value of sin θ + tan θ = ?

$\frac{216}{65}$

Given :-

PQ (H) = 13  , PR (P) = 12   & QR = ?

By using pythagoras theorem,

P² + B² = H²

12² + B² = 13²

144 + B² = 169

B² = 25

B = 5

Now,

sin θ + tan θ

= \(\frac{P}{H}\) + \(\frac{P }{B}\)

= \(\frac{12}{13}\) + \(\frac{12 }{5}\)

= \(\frac{60 + 156}{65}\)

= \(\frac{216}{65}\)