sin2 (120° - A) + sin2 A + sin2 (120

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

sin² (120° - A) + sin² A + sin² (120+A) is equal to ?

Options:

\(\frac{3}{2}\)

\(\frac{5}{16}\)

\(\frac{1}{3}\)

\(\frac{7}{16}\)

Correct Answer:

\(\frac{3}{2}\)

Explanation:

Let A = 60°

sin² (120°-60°) + sin² (60°) + sin² (180°)

= sin² 60° + sin² 60° + sin² 180°

= \(\frac{3}{4}\) × 2 + 0 = \(\frac{3}{2}\)