sin2 (120° - A) + sin2 A + sin2 (120+A) is equal to ?
Answer & explanation
Correct answer: option 1
Let A = 60°
sin2 (120°-60°) + sin2 (60°) + sin2 (180°)
= sin2 60° + sin2 60° + sin2 180°
= \(\frac{3}{4}\) × 2 + 0 = \(\frac{3}{2}\)
sin2 (120° - A) + sin2 A + sin2 (120+A) is equal to ?
Correct answer: option 1
Let A = 60°
sin2 (120°-60°) + sin2 (60°) + sin2 (180°)
= sin2 60° + sin2 60° + sin2 180°
= \(\frac{3}{4}\) × 2 + 0 = \(\frac{3}{2}\)