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The area bounded by the curve $y=\sin x$ and x- axis between $x=-\pi$ and $x=\pi$ is. |
4 2 0 $\pi$ |
4 |
The correct answer is Option (1) → 4
Area of (I = II = III = IV) by symmetry So area = 4 × Area I $=4×\int\limits_{0}^{π/2}\sin xdx$ So $4×[-\cos x]_{0}^{π/2}$ = 4 units |
