A solenoid has a core of a material with relative permeability 400. The windings of the solenoid are insulated from the core and carry a current of 1 A. If the number of turns is 800 per metre, the magnetic field inside solenoid will be |
0.40 T 4.02 T 40.2 T 0.04 T |
0.40 T |
The correct answer is Option (1) → 0.40 T Given: Relative permeability, $\mu_r = 400$ Current, $I = 1 \ \text{A}$ Number of turns per metre, $n = 800 \ \text{turns/m}$ Magnetic field inside a solenoid: $B = \mu_0 \mu_r n I$ Where $\mu_0 = 4\pi \times 10^{-7} \ \text{H/m}$ Substitute values: $B = (4 \pi \times 10^{-7}) \cdot 400 \cdot 800 \cdot 1$ $B = 4 \pi \times 10^{-7} \cdot 320,000 = 1.28 \pi \times 10^{-1} \ \text{T}$ $B \approx 0.402 \ \text{T}$ Magnetic field inside solenoid: $B \approx 0.402 \ \text{T}$ |