What is the area of a sector of a circle of radius 14 cm and central angle 45° ? (Take π = $\frac{22}{7}$)
Answer & explanation
Correct answer: option 2
We already know that,
Area of sector = \(\frac{ θ }{360}\) πr2
We have,
Radius of sector (r) = 14 cm
Central angle (θ) = 45°
Area of sector = \(\frac{45}{360}\) × \(\frac{22}{7}\) × 14 × 14 = 77 cm2