What is the area of a sector of a circle of radius 14 cm and central angle 45° ? (Take π = $\frac{22}{7}$)

70 cm2 77 cm2 11 cm2 67 cm2

77 cm2

We already know that, Area of sector = \(\frac{ θ }{360}\) πr2 We have, Radius of sector (r) = 14 cm Central angle (θ) = 45°  Area of sector = \(\frac{45}{360}\) × \(\frac{22}{7}\) × 14 × 14 = 77 cm2