An electromagnetic wave going through vaccum is described by $E=E_0Sin (kx-ωt)$. $B = B_0Sin (kx – ωt)$ then:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $E_0k=B_0ω$
Given that the electric field E and magnetic field B of an EM wave in a vacuum is,
$E=E_0\sin(kx-ωt)$
$B=B_0\sin(kx-ωt)$
and,
$E_0=cB_0$ ....(1)
$c=\frac{ω}{k}$ ....(2)
from (1) and (2)
$E_0k=ωB_0$