The LCM of two numbers is 168 and their HCF is 12. If the difference between the numbers is 60, then the sum of the numbers is?
Answer & explanation
Correct answer: option 1
LCM = HCF (a × b)
168 = 12 (a × b)
ab = 14, ⇒ a = 7, b = 2 (possible factors)
So, numbers are⇒ 12a, 12b
⇒ 12 × 7, 12 × 2 = 84, 24