The HCF and the LCM of two numbers are 5 and 120 respectively. If the sum of the two numbers is 55, then the sum of the reciprocals of these two numbers is equal to? |
\(\frac{55}{601}\) \(\frac{11}{120}\) \(\frac{120}{11}\) \(\frac{601}{55}\) |
\(\frac{11}{120}\) |
\(\frac{1}{a}\) + \(\frac{1}{b}\) = \(\frac{a + b}{ab}\) = \(\frac{55}{5 × 120}\) = \(\frac{11}{120}\) |