Which of the following option shows the Brewster's law in polarisation of light? |
$\mu \sin i_B=1$ $\mu \cos i_B=1$ $\mu \cot i_B=1$ $\mu \tan i_B=1$ |
$\mu \cot i_B=1$ |
The correct answer is Option (3) → $\mu \cot i_B=1$ Brewster's law states that the reflected light is completely polarised when the angle of incidence $(i_{B})$ satisfies the relationship- $\tan i_{B}=μ$ $⇒\frac{μ}{\tan i_{B}}=μ1$ $⇒\mu \cot i_B=1$ |