When a convex lens of glass is immersed in water, its power will |
increase decrease remain the same become zero |
decrease |
The correct answer is Option (2) → decrease Power of a lens is given by: $P = \left(\frac{n_{lens}}{n_{medium}} - 1\right)\left(\frac{1}{R_1} - \frac{1}{R_2}\right)$ When the lens is in air: $n_{medium} = 1$ When immersed in water: $n_{medium} = 1.33$ Since $\frac{n_{lens}}{n_{medium}} - 1$ decreases in water, the effective power decreases. Correct option: decrease |