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Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Linear Programming

Question:

The feasible region for a LPP is shown in the following figure. Let $z=3 x-4 y$ be the objective function. Minimum value of Z occurs at

Options:

(6, 8)

(0, 0)

(0, 8)

(5, 0)

Correct Answer:

(0, 8)

Explanation:

The correct answer is Option (3) - (0, 8)

corner points  $Z=3x-4y$
$A(0,0)$ $Z_A=0$
$B(0,8)$ $Z_B=-32$
$C(4,10)$ $Z_C=-28$
$D(6,8)$ $Z_D=-14$
$E(6,3)$ $Z_E=-2$
$F(5,0)$ $Z_F=15$

Minimum value at (0, 8)

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