Find the value of x if \(\begin{vmatrix}3 & 4 \\3 & 1 \end{vmatrix}\) = \(\begin{vmatrix}3 & 3 \\5 & x \end{vmatrix}\)

8 -8 2 -2

2

On solving the determinants we get 3-12 = 3x-15 -9 = 3x-15 6 = 3x x=2