Practicing Success
$\int\limits_0^{\pi / 2} \sin 2 x \ln \tan x d x=$ |
2 0 1 None of these |
0 |
$I=\int\limits_0^{\pi / 2} \sin 2 x \ln (\tan x) d x$ ....(1) $I=\int\limits_0^{\pi / 2} \sin 2\left(\frac{\pi}{2}-x\right) \ln \tan \left(\frac{\pi}{2}-x\right) d x$ $I =\int\limits_0^{\pi / 2} \sin 2 x \ln (\cot x) d x$ ....(2) Adding (1) and (2) $2I=\int\limits_0^{\pi / 2} \sin 2 x[\ln (\tan x)+\ln (\cot x)] d x=\int\limits_0^{\pi / 2} \sin 2 x \ln 1 d x=0$ |