If cosec θ = 1/4x + x, find cosec θ + cot θ

cosec θ = \(\frac{1}{4x}\)+ x

cosec θ = \(\frac{4x^2+1}{4x}\)

Put x = 1

cosec θ = \(\frac{5}{4}\)

Now cosec θ + cot θ

= \(\frac{5}{4}\) + \(\frac{3}{4}\) = \(\frac{8}{4}\)

= 2 or we can say

= 2x