Practicing Success
If cosec θ = \(\frac{1}{4x}\)+ x, find cosec θ + cot θ |
3x 2x x 4x |
2x |
cosec θ = \(\frac{1}{4x}\)+ x cosec θ = \(\frac{4x^2+1}{4x}\) Put x = 1 cosec θ = \(\frac{5}{4}\) Now cosec θ + cot θ = \(\frac{5}{4}\) + \(\frac{3}{4}\) = \(\frac{8}{4}\) = 2 or we can say = 2x |