Expand: $(4a+3b+2c)^{2}$

$16a^{2}-9b^{2}+4c^{2}-24ab+12bc-16ca$ $16a^{2}+9b^{2}+4c^{2}+24ab+12bc+16ca$ $4a^{2}+3b^{2}+2c^{2}+24ab+12bc+16ca$ $16a^{2}+9b^{2}+4c^{2}-24ab-12bc-16ca$

$16a^{2}+9b^{2}+4c^{2}+24ab+12bc+16ca$

Expand: $(4a+3b+2c)^{2}$ (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ac) So, $(4a+3b+2c)^{2}$ = $16a^{2}+9b^{2}+4c^{2}+24ab+12bc+16ca$