Expand: $(4a+3b+2c)^{2}$
Answer & explanation
Correct answer: option 2
Expand: $(4a+3b+2c)^{2}$
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ac)
So, $(4a+3b+2c)^{2}$ = $16a^{2}+9b^{2}+4c^{2}+24ab+12bc+16ca$
Expand: $(4a+3b+2c)^{2}$
Correct answer: option 2
Expand: $(4a+3b+2c)^{2}$
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ac)
So, $(4a+3b+2c)^{2}$ = $16a^{2}+9b^{2}+4c^{2}+24ab+12bc+16ca$