Practicing Success
Practicing Success
CUET Preparation Today
If $x^2y +yx^3=5x+3 ,$ then $\frac{dy}{dx}= $ |
$\frac{5}{2x+3x^2-3}$ $-\frac{3x^2y-2xy}{x^2+x^3-3}$ $\frac{5-3x^2y-3x}{x^2+x^3-3}$ $\frac{5-3x^2y-2xy}{x^2+x^3-3}$ |
$\frac{5-3x^2y-2xy}{x^2+x^3-3}$ |
