Practicing Success
In a young's double slit experiment, slits are illuminated by a monochromatic source of wavelength 6000 Å and fringes are obtained. If screen is moved by a distance of 5 cm towards slits, change in fringe width is $3 × 10^{–5} m$. Then separation between the slits will be |
1 mm 1.2 mm 1.5 mm 1.63 mm |
1 mm |
$β=\frac{λD}{d}$ and $β'=\frac{λD'}{d}$ $∴β-β'=\frac{λ(D-D')}{d}$ or $d=\frac{λ(D-D')}{(β-β')}$ $=\frac{6000×10^{-10}×5×10^{-2}}{3×10^{-5}}m=10^{-3}m=1mm$ |