CUET Preparation Today
The binding energy per nucleon for ${^{56}_{}Fe}$ is |
8.75 MeV 11.26 MeV 9.96 MeV 4.89 MeV |
8.75 MeV |
The correct answer is Option (1) → 8.75 MeV Total binding energy of $^{56}Fe$ is approximately $492 \, \text{MeV}$. Binding energy per nucleon = $\frac{492}{56}$ $= 8.79 \, \text{MeV (approx)}$ Answer: $8.8 \, \text{MeV per nucleon (approx)}$ |
