The force of attraction between two charges separated by a distance in the air medium is F. If the medium air is replaced by a dielectric medium of dielectric constant K, the force of attraction between the charges will become

$F K^{-1}$

The correct answer is Option (2) → $F K^{-1}$

Coulomb's law in a medium of dielectric constant $K$:

$F_\text{medium} = \frac{F_\text{air}}{K}$

Where $F_\text{air} = F$ is the force in air.

Thus, the force in the dielectric medium:

$F' = \frac{F}{K}$

Final Answer: $F' = \frac{F}{K}$