The force of attraction between two charges separated by a distance in the air medium is F. If the medium air is replaced by a dielectric medium of dielectric constant K, the force of attraction between the charges will become
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( FK^{-1} \)
By Coulomb's law, the force between two charges in a medium is reduced by the dielectric constant of the medium, because the medium's permittivity is \( \varepsilon = K\varepsilon_0 \).
\( \displaystyle F = \frac{1}{4\pi\varepsilon_0}\,\frac{q_1 q_2}{r^{2}} \)
\( \displaystyle F' = \frac{1}{4\pi K\varepsilon_0}\,\frac{q_1 q_2}{r^{2}} = \frac{F}{K} = FK^{-1} \)