Two circles touch each other externally at T. Rs is a direct common tangent to the two circles touching the circles at P and Q. ∠TPQ = 42o.∠PQT (in degrees) is :
Answer & explanation
Correct answer: option 1
We know that,
∠QTP = 90°
In ΔQPT, ∠QPT + ∠QTP + ∠PQT = 180°
= 42° + 90° + ∠PQT = 180°
= ∠PQT = 180° - 90° - 42° = 48°