Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Thermodynamics

Question:

Forty-four grams of CO2 at 27oC is mixed with 16 g of O2 at 37oC. The temperature of the mixture is about :

Options:

31.5oC

27oC

37oC

30oC

Correct Answer:

30oC

Explanation:

Let t be the temperature of mixture.

Heat gained by CO2 = Heat lost by O2

\(\Rightarrow \mu_1 C_{v_1} \Delta T_1 = \mu_2 C_{v_2} \Delta T_2\)

\(\Rightarrow \frac{44}{44} (3R) (t - 27) = \frac{16}{32} (\frac{5}{2}R) (37 - t)\)

\(\Rightarrow 3(t - 27) = \frac{5}{4}(37 - t)\)

t = 30oC