If \(2A=5B=6C\), then \(A:B:C\) is equal to:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 15 : 6 : 5
When \(2A\), \(5B\) and \(6C\) are equal, set each of them equal to a common multiple of 2, 5 and 6. The smallest one is 30.
\(2A=5B=6C=30t\)
\(\displaystyle A=\frac{30t}{2}=15t\)
\(\displaystyle B=\frac{30t}{5}=6t\)
\(\displaystyle C=\frac{30t}{6}=5t\)
So \(A:B:C=\) 15 : 6 : 5.