A 1 KW signal is transmitted using a communication channel which provides attenuation at the rate of 2 dB per km. If the communication channel has a total length of 5 km, what is the power of the signal received ?
(gain in dB = 10 log \(\frac{P_{o}}{P_{i}}\)
Answer & explanation
Correct answer: option 2
Pi = 1 kW = 1000 W
length of path = 5 Km
Loss of power at a distance of 5 km = 2 x 5 = 10 dB
gain in dB = -10 log \(\frac{P_{i}}{P_{o}}\)
Po = 100 W