Practicing Success
Practicing Success
CUET Preparation Today
If a + b + c = 0, then find the value of \(\frac{a^3}{a^3 - abc}\) + \(\frac{b^3}{b^3 - abc}\) + \(\frac{c^3}{c^3 - abc}\) ? |
0 1 2 5 |
2 |
We have 3 variables and only one equation. so let, c = 0 ⇒ a + b = 0 Put in find → \(\frac{a^3}{a^3}\) + \(\frac{b^3}{b^3}\) + 0 = 1 + 1 = 2 |
