A charged particle with charge q and mass 'm' is moving with velocity 160 ms-1 in the region of magnetic field B at an angle 60° with the direction of \(\vec{B}\). The pitch of helix formed by particle will be:
Answer & explanation
Correct answer: option 3
$ \text{Time period T }= \frac{2\pi m}{qB} $
$ Pitch = \text{Component of velocity along magnetic field}\times \text{Time Period} = \frac{2\pi m}{qB} \times vcos60^o = \frac{2\pi m}{qB} \times 80 = \frac{160\pi m}{qB}$