Expand $x^2 + 2x + 3$ and x = -2.

(x − 2)2 − 2 (x + 2) + 3 (x + 2)2 − 2 (x + 2) + 3 (x + 2)2 + 2 (x + 2) + 3 (x − 2)2 − 2 (x - 2) - 3

(x + 2)2 + 2 (x + 2) + 3

Given,  x2 + 2x + 3 x = –2 If x = – 2 then  x + 2 = 0 Now we have to expand only options 2 and 3, As in options 1 and 4, the first term is (x - 2) From option 2,  = (x + 2)2 – 2(x + 2) + 3 = x2 + 4x + 4 - 2x - 4 + 3 = x2 + 2x + 3 ( satisfied) So the answer will be = (x + 2)2 + 2 (x + 2) + 3