What is the amount of urea to be dissolved in 500 g of water to produce a depression of 0.186oC in the freezing point ? (Kf for water = 1.86 K/m)

0.6 g 60 g 3 g 6 g

3 g

Depression in freezing point, ΔTf = Kf x m 0.186 = 1.86 x \(\frac{\frac{x}{60}}{500}\) x 1000 x = 3 g