In Young's double slit experiment, the light has a frequency of $6 × 10^{14} Hz$ and the distance between the centers of adjacent fringes is 0.75 mm. If the screen is 1.5 m away, what is the distance between the slits?

$10^{-2} m$ $10^{-3} m$ $10^{-4} m$ $10^{-6} m$

$10^{-3} m$

The correct answer is Option (2) → $10^{-3} m$