CUET Preparation Today
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$12\Omega , 6\Omega , 4\Omega \text{Are connected in parallel} R_p = 2\Omega$ $ 2\Omega and 20\Omega \text{are in parallel } R_p'= \frac{20}{11}\Omega$ $ \frac{20}{11}\Omega , 5\Omega , 3\Omega\text{ are in series } R_{eq}= 9.85\Omega$ |
