$10^{18}$ electrons pass from point A to point B in 0.1 s in a conductor. The value of the current is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 1.6 A
$\text{Given: Number of electrons } n = 10^{18},~ t = 0.1~\text{s}$
$\text{Charge of one electron } e = 1.6 \times 10^{-19}~\text{C}$
$\text{Total charge transferred: } Q = n \cdot e = 10^{18} \cdot 1.6 \times 10^{-19} = 0.16~\text{C}$
$\text{Current: } I = \frac{Q}{t} = \frac{0.16}{0.1} = 1.6~\text{A}$
$\text{Answer: } I = 1.6~\text{A}$