If decreasing 111 by x% gives the same result as increasing 37 by x%, then x% of 570 is what percentage more than (x -10)% of 1140 ? (correct to nearest integer)

37.5%

let x% = f

According to question ,

 111 (1 - f) = 37 (1 + f)

\(\frac{1 - f}{1 + f}\) = \(\frac{1}{3}\)

 \(\frac{1}{f}\) = \(\frac{4}{2}\) = \(\frac{2}{1}\)

x% = f = \(\frac{1}{2}\) × 100 = 50%

Now →

  \(\frac{570 × 50}{1140 × (50 - 10)%}\) = \(\frac{570 × 50}{1140 × 40}\)

 = \(\frac{5}{8}\)

Required percentage = \(\frac{8-5}{8}\)  = \(\frac{5}{8}\) 

= 37.5%