Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

General Ability

Topic

Odd One Out/Classification

Question:

Four letter-clusters have been given, out of which three are alike in some manner and one is different. Select the letter-cluster that is different.

Options:

LRPV

SYGM

DBJH

CNDV

Correct Answer:

CNDV

Explanation:

The logic followed here is ;

Sum of positional value of alphabet

LRPV 12 + 18 + 16 + 22 = 68 Even

SYGM 19 + 25 + 7 + 13 = 64 even

DBJH 4 + 2 + 10 + 8 = 24 even

CNDV ⇒ 3 + 14 + 4 + 22 = 43 prime odd number