If one side of a square is increased by 30%, by what percentage another side is reduced so that its area remains same?
Answer & explanation
Correct answer: option 3
Area = Side1 × Side2
*(When area is constant, then the relation b/w sides are inversely proportional)
Side1 : 10 : 13
Side2 : 13 : 10
Side2 should be reduced by = 13 - 10 = 3
So, Reduce percent = \(\frac{3}{13}\) × 100 = 23\(\frac{1}{3}\)%