If one side of a square is increased by 30%, by what percentage another side is reduced so that its area remains same?

15% 76\(\frac{12}{13}\)% 23\(\frac{1}{3}\)% 30%

23\(\frac{1}{3}\)%

Area = Side1 × Side2 *(When area is constant, then the relation b/w sides are inversely proportional) Side1  :  10  :   13 Side2  :  13  :   10 Side2 should be reduced by = 13 - 10 = 3 So, Reduce percent = \(\frac{3}{13}\) × 100 = 23\(\frac{1}{3}\)%