An object A is charged by rubbing with an object B. In the process $10^9$ electrons are transferred from A to B. Charge developed on A will be: (Take electronic charge $e= 1.602 × 10^{-19} C$)

$1.6 × 10^{-10} C$

The correct answer is Option (4) → $1.6 × 10^{-10} C$

The charge transferred to object A is,

Charge, $Q=n×e$

$=10^9×1.6×10^{-19}$

$=1.6×10^{-10}C$