Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

The plates of a parallel plate capacitor are d= 2.0 mm apart and each plate has an area A = 2.0 x 10–4 m2. The space between the plates is completely filled with a linear dielectric material  of dielectric constant K = 2.0.  The capacitor is connected to a source of emf of 2.0 x 102 V.  The electric field between the plates is

Options:

3.0 x 105 Vm–1     

 2.0 x 105 Vm–1

5.0 x 104 Vm–1  

1.0 x 105 Vm–1

Correct Answer:

1.0 x 105 Vm–1

Explanation:

$ E = \frac{V}{d} = \frac{2\times 10^2}{2\times 10^{-3}} = 10^5 V/m$