Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

Dimensional formula of latent heat

Options:

$[M^0L^2T^{-2}]$

$[MLT^{-2}]$

$[ML^2T^{-2}]$

$[ML^2T^{-1}]$

Correct Answer:

$[M^0L^2T^{-2}]$

Explanation:

Q = mL

⇒L= $\frac{Q}{m}$

⇒[L] = $[\frac{Q}{m}]$ = $\frac{[ML^2T^{-2}]}{[M]}$ = $[M^0L^2T^{-2}]$