The difference between the length and breadth of a rectangle is 25 meters. If the perimeter of this rectangle is 210 meters, what is its area?

2600 SQ m

Given:

• $L - B = 25$
• Perimeter = $210\text{ m}$

Perimeter of a rectangle:

$2(L + B) = 210$

$L + B = 105$

Now solve:

$L + B = 105$

$L - B = 25$

Adding the equations:

$2L = 130$

$L = 65$

Then,

$B = 105 - 65 = 40$

Area of the rectangle:

$\text{Area} = L \times B = 65 \times 40 = 2600\text{ m}^2$