Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:

The solution of the differential equation $\cos x \sin y d x+\sin x \cos y d y=0$, is

Options:

$\frac{\sin x}{\sin y}=C$

$\cos x+\cos y=C$

$\sin x+\sin y=C$

$\sin x \sin y=C$

Correct Answer:

$\sin x \sin y=C$

Explanation:

We have,

$\cos x \sin y d x+\sin x \cos y d y=0$

$\Rightarrow \sin y d(\sin x)+\sin x d(\sin y)=0$

$\Rightarrow d(\sin x \sin y)=0$

On integrating, we get $\sin x \sin y=C$