What is the area (in sq cm) of a rectangle of perimeter 56 cm and breadth 22 cm?

122 cm2 132 cm2 136 cm2 162 cm2

132 cm2

Perimeter of rectangle = 2 (l + b) 56 = 2 (l + 22) l = \(\frac{56}{2}\) – 22 = 6 cm. area = l × b = 6 × 22 = 132 cm2