What is the area (in sq cm) of a rectangle of perimeter 56 cm and breadth 22 cm?
Answer & explanation
Correct answer: option 2
Perimeter of rectangle = 2 (l + b)
56 = 2 (l + 22)
l = \(\frac{56}{2}\) – 22 = 6 cm.
area = l × b = 6 × 22 = 132 cm2
What is the area (in sq cm) of a rectangle of perimeter 56 cm and breadth 22 cm?
Correct answer: option 2
Perimeter of rectangle = 2 (l + b)
56 = 2 (l + 22)
l = \(\frac{56}{2}\) – 22 = 6 cm.
area = l × b = 6 × 22 = 132 cm2