On putting $\frac{y}{x}=v$ the differential equation $\frac{d y}{d x}=\frac{2 x y-y^2}{2 x y-x^2}$ is transformed to
Answer & explanation
Correct answer: option 2
Putting $y=v x$ and $\frac{d y}{d x}=v+x \frac{d v}{d x}$, given differential equation reduces to
$v+x \frac{d v}{d x}=\frac{2 v-v^2}{2 v-1} \Rightarrow 3 v(1-v) d x=x(2 v-1) d v$